Physics, asked by questioner68, 1 month ago

differentiate y = 1/✓2x​

Answers

Answered by abhishekshibu9267
0

Answer:

y=\frac{1}{\sqrt{2}x } \\\\y=(\sqrt{2} x)^-1\\\\\frac{dy}{dx}= -1\frac{1}{(\sqrt{2} x)^2}. (\frac{1}{2\sqrt{2} x}) \\\\\frac{dy}{dx}= \frac{-1}{2 x^2}. (\frac{1}{2\sqrt{2} x}) \\\\\frac{dy}{dx}= \frac{-1}{4\sqrt{2}x^3}\\\\

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