Differentiate y= 2tanx/2 prove that dy/dx= 2/1+cosx
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Answered by
31
y=2tanx/2
dy/dx=2sec^2x/2..1/2
=sec^2x/2
=1/cos^2x/2
cos^2x/2=1+cosx/2
put this value above
dy/dx=2/1+cosx
dy/dx=2sec^2x/2..1/2
=sec^2x/2
=1/cos^2x/2
cos^2x/2=1+cosx/2
put this value above
dy/dx=2/1+cosx
Answered by
10
Given: y = 2 tan(x/2)
To prove: dy/dx = 2/(1+cos(x))
Proof: y = 2 tan(x/2)
dy/dx = 2× sec^(x/2) × (1/2)
dy/dx= sec^(1/2)
dy/dx= 1/(cos^(1/2)) [let eq 1]
As, cos^(x/2) = [1+ cos(x)]/ 2
Putting this in eq 1 we get,
dy/dx = 2/(1+cos(x))
Hence Proved.
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