Physics, asked by devashish1135, 1 day ago

Differentiate y=4x³+3x²+x+7with respect to x.

Answers

Answered by jaymodha10965
1

Answer:

dy/dx=12x^2+6x+1

Explanation:

Your question:-

Differentiate y=4x³+3x²+x+7 with respect to x

Your solution:-

y=4x³+3x²+x+7

 \frac{dy}{dx} =  \frac{d(4{x}^{3} + 3 {x}^{2} + x + 7)  }{dx}

Using formula:-

x {}^{n}  =  \frac{d(x {}^{n}) }{dx} = nx {}^{n - 1}

 \frac{dy}{dx}  = 4 \times 3x {}^{2} + 3 \times 2x {}^{1}   + 1 + 0

\frac{dy}{dx}  = 12x {}^{2}  + 6x + 1

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