differentiate y=ax3+bx2+cx+d where a,b,c,d are constant
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1
Answer:
3ax2+2bx+c
Step-by-step explanation:
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dy/dx= d(ax³+bx²+cx+d)/dx
=> d(ax³)/dx + d(bx²)/dx + d(cx)/dx + d(d)/dx
=> 3ax² + 2bx + c + 0
Hence, answer is 3ax²+2bx+x = 0
Hope it's helpful
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