differentiate y=cos(a^3+x^3)
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Answered by
0
Answer:
y'= -sin(a^3+x^3) 3x^2 where a is constant
Answered by
11
Answer:
- 3 x² sin ( a³ + x³ )
Step-by-step explanation:
Given :
y = cos ( a³ + x³ )
Now diff. w.r.t. x
d y / d x = d ( cos ( a³ + x³ ) / d x
Applying chain rule here :
d y / d x = - sin ( a³ + x³ ) ( a³ + x³ )'
d y / d x = - sin ( a³ + x³ ) ( 3 x² )
d y / d x = - 3 x² sin ( a³ + x³ )
Therefore , final answer is - 3 x² sin ( a³ + x³ ) .
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