Question

differentiate y=cosx(tanx)​

Answer 1

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$\longmapsto \sf y = \cos x. \tan x$

$\longmapsto \sf \frac{dy}{dx} = \frac{d}{dx} ( \cos x. \tan x)$

$\longmapsto \sf \frac{dy}{dx} = \cos x. { \sec}^{2}x + \tan x.( - \sin x)$

$\longmapsto \sf \frac{dy}{dx} = \cos x. { \sec}^{2}x - \tan x. \sin x$

Formula Used :-

$\longmapsto \sf \frac{d}{dx} (uv) = u .\frac{d}{dx}(v) + v. \frac{d}{dx} (u)$