Question

Differentiate : y=(cx+d)^9​

Answer 1

Answer:

$y = (cx + d) ^{9} \\ = > \frac{dy}{dx} = \frac{d}{dx} (cx + d) ^{9}\\ = > \frac{dy}{x} = 9(cx + d) {}^{8} \times \frac{d}{dx} (cx + d) \\ = 9 {(cx + d)}^{8} \times c$