Question

Differentiate: y = e ^ x * (x + log x)​

Answer 1

Answer:

Differentiation of e^(x*logx) is (1 + logx)e^(x*logx). = 1 + logx ).

Answer 2

Differentiate of e^(x*logx)is ( 1+ logx)e^(x*logx)=1+ logx