Math, asked by Arunav5, 1 year ago

differentiate y=e^xsinxcos² x

Answers

Answered by kvnmurty
1
dy/dx = e^x * \frac{d}{dx} (sin\ x\ cos^2x)+sin\ x\ cos^2x * \frac{d}{dx}e^x\\ \\e^x* [sinx\ 2cos\ x(-sinx)+cos^2x\ cos\ x ] + sinx\ cos^2x\ e^x\\ \\e^x\ cos\ x [ 3cos^2x-2 +\frac{1}{2}sin2x ]\\\\= \frac{1}{2}e^x\ cos\ x [ 3cos2x -1+sin2x]\\


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or, another way:

dy/dx = \frac{d}{dx}e^x [ sinx - sin^3x]=\\ \\=e^x[ sin\ x - sin^3x + cos\ x - 3sin^2x\ Cos\ x ]\\ \\=e^x[ sinx+cosx-sin^2x( sinx+3cosx)]

Arunav5: another way by multiplying 2/2 as it gets into the trignometry formula
kvnmurty: what is the problem ? why did you report the error?
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