differentiate Y equal to x power x
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Hey MATE!!
Answer to your question is in the above attachment.
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Answered by
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y= x^x
taking log both sides
logy = xlogx
now differeciating wrt x
1/y ( dy/dx)= d/dx(xlogx)= x ×1/x+ logx
dy/dx=y (1+logx)= x^x ( 1+logx)
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