Question

differentiate y=f(x3) and f(x)=e^8x, then find dy/dx​

Answer 1

PT = y√(1+ cot2 θ )=y√(1+(dx/dy)2 ). Also, PN = y sec q = y√(1+tan2 θ )=y√(1+(dy/dx)2 ). => Length of the normal, PN = |y| √(1+(dy/dx)2 ).