Question

Differentiate y is equals to 2 by sin theta + root 3 cos theta

Answer 1

y = 2Sin theta  + √3 Cos theta


dy/d (theta) = 2Cos theta - √3 Sin theta

Remember

d/dy Sin theta = Cos theta

and

d/dy  Cos Theta = - Sin theta

Answer 2

Answer:

Step-by-step explanation:

The given equation is:

y=$\frac{2}{sin{\theta}}+\sqrt{3}cos{\theta}$

y=$2cosec{\theta}+\sqrt{3}cos{\theta}$

Differentiating the above equation with respect to ${\theta}$, we get

$\frac{dy}{d{\theta}}=2(-cosec{\theta}cot{\theta})+\sqrt{3}(-sin{\theta})$

$\frac{dy}{d{\theta}}=-2cosec{\theta}cot{\theta}-\sqrt{3}sin{\theta}$

$\frac{dy}{d{\theta}}=-(cosec{\theta}cot{\theta}+\sqrt{3}sin{\theta})$