Question

differentiate y = sec √x
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Answer 1

$y=sec (\sqrt{x} )\\\frac{dy}{dx}=\frac{d(sec\sqrt{x})}{(\sqrt{x} )} * \frac{d(\sqrt{x})}{dx}\\\frac{dy}{dx}= tan(\sqrt{x} )*sec\sqrt({x}) * \frac{1}{2\sqrt{x} } \\\frac{dy}{dx}=\frac{tan(\sqrt{x} )*sec\sqrt({x})}{2\sqrt{x}}$