differentiate, y= sin^2 (3x + 1)
Answers
Answered by
3
Answer:
2sin(3x+1).cos(3x+1).3
Step-by-step explanation:
u can find it by chain rule.
Answered by
7
Answer: 6sin(3x+1)cos(3x+1)
Step-by-step explanation:
y = sin²(3x+1)
Differentiate both sides w.r.t. x
y' = 2sin(3x+1) dy/dx[sin(3x+1)]
= 2sin(3x+1).cos(3x+1).3
y' = 3sin[2(3x+1)] or 6sin(3x+1)cos(3x+1)
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