Differentiate y = (sin) (logx) with respect to x
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12th
Maths
Continuity and Differentiability
Derivatives of Composite Functions and Chain Rule
Find dydx of y = sin(logx) ?
MATHS
Find
dx
dy
of y=sin(logx) ?
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ANSWER
Let,y=sin(logx)
Now Differentiate y with respect to x
then
dx
dy
=
dxsin(logx)
d
dx
dy
=
dx(logx)
cos(logx).d
dx
dy
=cos(logx).
x
1
So,the answer is cos(logx).(
x
1
)
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