Question

differentiate y = sinx³

Answer 1

y(x) =sin(x) ^3

u=x^3 so yx= sinu

dy/dx = du/dx ✖️ dy/du

Now, du/dx= 3x^2

dy/du = cos(u)

dy/du= (3x^2) {cos(u)}

Substituting x^3 back in value of u-

dy/dx = 3x^2 cosx^3