Question

differentiate y= tan(√x), find dy/dx​

Answer 1

Answer:

sec²(√x) /2√x

Step-by-step explanation:

Using d(tanA)/dA = sec²A

dAⁿ/dA = nA^(n-1)

Here,

=> dy/dx = d(tan√x)/dx

Using chain rule, multiply as well as

divide by d√x:

=> d(tan√x)/d(√x) * d(√x)/dx

=> sec²(√x) * (½)x^(½ - 1)

=> sec²(√x) * ½ x^(-½)

=> sec²(√x) * 1/2√x

=> sec²(√x) / 2√x