Math, asked by abubakar12211221, 4 months ago

differentiate y = \sqrt{x}(x2-1)

Answers

Answered by yoyowhat583
1

Answer:

The Math.sqrt() function returns the square root of a number, that is

\forall x \geq 0, \mathtt{Math.sqrt(x)} = \sqrt{x} = \text{the unique} \; y \geq 0 \; \text{such that} \; y^2

Step-by-step explanation:

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Answered by Anonymous
27

Answer:

differentiate y =√x x²-1

Step-by-step explanation:

y'=1 (x2+1)3 2

y=x √x2+1

y=f g

y'=gf'−fg' g2

y'=√x2+1−x⋅1 2√x2+1⋅(2x) (√x2+

y'=√x2+1−x2 √x2+1 x2+1

y'=(x2+1)−x2 (x2+1)3 2

y'=1 (x2+1)3 2

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