Question

differentiate y=x^sinx + sin^(-1) x²​

Answer 1

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Answer 2

y=1−x2xsin−1x

y1−x2=xsin−1x

Differentiating both sides w.r.to x, we get

y⋅21−x2(−2x)+1−x2dxdy=x⋅1−x21+sin−1x

−xy+(1−x2)dxdy=x+1−x2sin−1x

−xy+(1−x2)dxdy=x+1−x2⋅xy1−

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