Question

Differentiate y = √x + tanx - x²​

Answer 1

$\frac{dy}{dx} = \frac{dx^{1/2} }{dx} + \frac{dtanx}{dx} - \frac{dx^{2} }{dx} \\= \frac{1}{2\sqrt{x} } + sec^{2}x - 2x$