Question

differentiate

y = x² + x + 8​

Answer 1

Answer:

$\frac{dy}{dx} = 2x + 1$

Step-by-step explanation:

differentiate with repect to x

$y = {x }^{2} + x + 2$

$\frac{dy}{dx } = \frac{d {x}^{2} }{dx} + \frac{dx}{dx} + \frac{d(2)}{dx}$

$\frac{dy}{dx} = 2x + 1 + 0$

$\frac{dy}{dx } = 2x + 1$

Hint:

$\frac{d {x}^{n}} {dx} = n {x}^{n - 1}$