Math, asked by znisha1980, 4 months ago

differentiation class 11​

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Answered by anthonypaulvilly
0

Answer:

aⁿ = naⁿ⁻¹                               solving y separately↓

1) d/dy (3y^{2/3}) = 3× 2/3  × y^{2/3 - 1} = y^{-1/3} = 1 / y^{1/3}   = y^{3}

                      = 2y³

2) d / dt ( t² + t³ + t⁴) = 2t + 3t² + 4t³

3) d / dx ( x^{3/2}  + 2x^{1/2}) = {3/2 × x^{3/2 - 1} }+ {2× 1/2 × x^{1/2 - 1}  )

                                     = 3x^{1/2} / 2 + x^{-1 / 2}

                                     = 3√x / 2 + 1 / √x

                                     = 3x + 2 / 2√x

Answered by ramdastarke0
0

Answer:

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