Question

differentiation of 1/√2x​

Answer 1

$y = \frac{1}{ \sqrt{2}x } \\ \frac{dy}{dx} = \frac{1. {x}^{ - 1} }{ \sqrt{2} } \\ \frac{dy}{dx} = \frac{ - 1}{ \sqrt{2} {x}^{2} }$