differentiation of 2x+3/x²-5
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Answer:
(-2x^2 + 6x - 10)/(x^2 - 5)^2
Explanation:
We have to differentiate f(x) = (2x - 3)/(x^2 - 5). Use the quotient rule.
f'(x) = (2*(x^2 - 5) - (2x - 3)* 2x)/(x^2 - 5)^2
=> (2x^2 - 10 - 4x^2 + 6x)/(x^2 - 5)^2
=> (-2x^2 + 6x - 10)/(x^2 - 5)^2
The required derivative is (-2x^2 + 6x - 10)/(x^2 - 5)^2
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