Question

differentiation of 5x^6+sinx-cotx​

Answer 1

ANSWER

Given,

y=cos[log(cotx)].

Now, differentiating both sides with respect to x we get,

dxdy=−sin[log(cotx)].cotx−cosec2x

or, dxdy=sin[log(cotx)].sinx.cosx1.

Answer 2

Answer:

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Explanation:

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