Question

Differentiation of a product
y = e θ(tan θ − θ)

Answer 1

Answer:

Product differentiation is what makes your product or service stand out to your target audience. It's how you distinguish what you sell from what your competitors do, and it increases brand loyalty, sales, and growth. Focusing on your customers is a good start to successful product differentiation.

Answer 2

$$y = \tan\theta(\sin\theta + \cos\theta)$$ $$y = [\tan\theta\sin\theta] + [\tan\theta\cos\theta]$$

y = \tan\theta(\sin\theta + \cos\theta)$$ $$y = [\tan\theta\sin\theta] + [\tan\theta\cos\theta]$$Using the Product Rule: $f'g + fg'$

y = \tan\theta(\sin\theta + \cos\theta)$$ $$y = [\tan\theta\sin\theta] + [\tan\theta\cos\theta]$$Using the Product Rule: $f'g + fg'$$$y' = [\sec^2\theta\sin\theta + \tan\theta\cos\theta] + [\sec^2\theta\cos\theta + (\tan\theta)(-\sin\theta)]$$

y = \tan\theta(\sin\theta + \cos\theta)$$ $$y = [\tan\theta\sin\theta] + [\tan\theta\cos\theta]$$Using the Product Rule: $f'g + fg'$$$y' = [\sec^2\theta\sin\theta + \tan\theta\cos\theta] + [\sec^2\theta\cos\theta + (\tan\theta)(-\sin\theta)]$$$$y' = \sec^2\theta\sin\theta + \tan\theta\cos\theta + \sec^2\theta\cos\theta -\sin\theta\tan\theta$$

y = \tan\theta(\sin\theta + \cos\theta)$$ $$y = [\tan\theta\sin\theta] + [\tan\theta\cos\theta]$$Using the Product Rule: $f'g + fg'$$$y' = [\sec^2\theta\sin\theta + \tan\theta\cos\theta] + [\sec^2\theta\cos\theta + (\tan\theta)(-\sin\theta)]$$$$y' = \sec^2\theta\sin\theta + \tan\theta\cos\theta + \sec^2\theta\cos\theta -\sin\theta\tan\theta$$At this point, I have no idea how to simplify it any further.