Physics, asked by bhavyadiwedi2906, 8 months ago

differentiation of cot^2 x​

Answers

Answered by Anonymous
1

Answer:

By formula

d/dx(x^n)=n.x^n-1.

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Answered by Anonymous
3

dy/dx = cot²x

dy/dx = d/dx . (cotx)²

dy/dx = 2cotx. d/dx . cotx

dy/dx = 2cotx . (- cosec²x)

•°• f'(x) = - 2cot. cosec²x

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