Differentiation of e^Sinx.....plz answer fast it's urgent
Answers
Answered by
0
Hey!!!...Here is ur answer
d/dx (e^sinx)
=> e^sinx d/dx (sinx)
=> cosx e^sinx
Hope it will help you
d/dx (e^sinx)
=> e^sinx d/dx (sinx)
=> cosx e^sinx
Hope it will help you
Answered by
1
HEY mate here is your answer.
It is a chain rule application question.
Hope it helps you.
^_^
It is a chain rule application question.
Hope it helps you.
^_^
Attachments:
Similar questions