Math, asked by ankitamahapatra364, 2 months ago

Differentiation of log base 10 (cosx)

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Answered by Anonymous
0

From change of base we have log10(x)=log10(x)=ln(x)ln(10) . 1ln(10) is just a constant multipler. Doing the problem this way gives a result of y'=1ln(10)⋅1x .

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