Math, asked by shruthi8256, 4 months ago

differentiation of log base 7 log x

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Answered by MsInnocent

0

Answer:

y = log7logx y = logelogxloge7 dydx = 1loge7 (1logx) ddxlog x dydx = 1loge7 1log x. 1x dydx = 1loge7x log x dydx = 1loge7x log x

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