Question

differentiation of log cos x

Answer 1

Answer:

Step-by-step explanation:

Let y = Log (cos x)

$\bold{\frac{dy}{dx} = \frac{1}{cos x}(-sin x) }$

$\bold{\frac{dy}{dx} = \frac{-sinx}{cos x} }$

$\bold{\frac{dy}{dx} = - Tan x }$

Thus the derivative of log(cos x) = - Tan x

→ Derivative of Log x = 1/x

→ Derivative of cos x = - sin x