Question

Differentiation of log (logx)...plz solve step by step

Answer 1

Hey!!!...Here is ur answer

d/dx [log (logx)]

=> 1/logx d/dx (logx)

=> 1/(x logx)

Hope it will help you

Answer 2

$\textbf{Answer :}$

Let, y = log (logx)

Now, differentiating both sides with respect to x, we get

dy/dx = d/dx {log (logx)}

= 1/(logx) d/dx (logx)

= 1/(logx) × (1/x)

= 1/(x logx),

which is the required derivative.

Rule :

d/dx (logx) = 1/x

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