Question

Differentiation of log (sinx)....give step by step solution

Answer 1

Hey!!!...Here is ur answer

d/dx [log (sinx)]

=1/sinx d/dx (sinx)

=cosx /sinx

=cot x

Hope it will help you

Answer 2

heya friend!!☺☺
here's your answer!!☺☺

Assuming log base 10:

Let u = sin(x)

du/dx = cos(x)

d/dx(log(u)) = 1/(ln(10) * u) * du/dx

d/dx(log(sin(x)) = (1/(ln(10) * sin(x)) * cos(x)

= cot(x)/(ln(10))

hope it helps you!!☺☺