Math, asked by kavyanshhero, 11 hours ago

Differentiation of log3 base x
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Answers

Answered by rahul2103
2

f(x)=logₓ3

Using the property:

logₐb=log₁₀b/log₁₀a

logₓ3=log3/logx

f(x)=log3/logx

f'(x)=log3 [d/dx(1/logx)]

Derivative of 1/logx=-1/x(logx)² (remember as fact)

f'(x)=-log3[1/x(logx)²]

Answered by mssingh8651
0

Answer:

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