Differentiation of log3 base x
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f(x)=logₓ3
Using the property:
logₐb=log₁₀b/log₁₀a
logₓ3=log3/logx
f(x)=log3/logx
f'(x)=log3 [d/dx(1/logx)]
Derivative of 1/logx=-1/x(logx)² (remember as fact)
f'(x)=-log3[1/x(logx)²]
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