Question

differentiation of sin^2 x​

Answer 1

2sinxcosx

Explanation:

diff(sinx.sinx)

sinxcosx+sinxcosx

2sinxcosx

Answer 2

dy/dx = d/dx . sin²x = d/dx . (sinx)²

dy/dx = 2.sinx . d/dx . sinx

dy/dx = 2sinx . cosx

•°• f'(x) = 2sinx.cosx