Question

Differentiation of (sin(3x²+4x⁴-2x³)) w.r.t x
Class 11 maths​

Answer 1

I am assuming you know how to find derivatives so I am gonna skip the derivation

y=2x^3 + 3x^2 - 36x + 7

dy/dx= 6x^2 + 6x - 36 + 0

We want dy/dx=0

So, 6x^2 +6x - 36 = 0

6( x^2 + x - 6 ) = 0

x^2 + x - 6 = 0

x^2 + 3x - 2x - 6 =0

x(x+3) -2(x+3) = 0

(x-2) (x+3)=0

So x=2 or x = -3

are the values of x for which dy/dx = 0