Differentiation of sin(logx)
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differentiate of sinx is cosx
Differentiate of logx is 1/x
So we have sin(logx) = coslogx.d/dxlogx
= cos(logx)1/x
Will be the answer 1/xcos(logx)
Differentiate of logx is 1/x
So we have sin(logx) = coslogx.d/dxlogx
= cos(logx)1/x
Will be the answer 1/xcos(logx)
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