Differentiation of sin(logx)
Answers
Answered by
3
differentiate of sinx is cosx
Differentiate of logx is 1/x
So we have sin(logx) = coslogx.d/dxlogx
= cos(logx)1/x
Will be the answer 1/xcos(logx)
Differentiate of logx is 1/x
So we have sin(logx) = coslogx.d/dxlogx
= cos(logx)1/x
Will be the answer 1/xcos(logx)
Similar questions
Math,
6 months ago
CBSE BOARD X,
6 months ago
Math,
1 year ago
English,
1 year ago
Physics,
1 year ago
Social Sciences,
1 year ago