Question

differentiation of sin square x square + 1​

Answer 1

Answer:

dx sin^2 x^2 + 1

= 2sin 2x

Answer 2

step by step explanation:

y = sin^2x^2 + 1

let x^2 = u

then, du/dx = 2x. ..........(1)

then, y= sin^2u + 1

==> dy/du= 2sinu.cosu + 0. ....(2)

now, dy/dx= dy/du X du/dx

therefore, from (1)&(2),

dy/dx. = 2sinucosu. X. 2x

==> 2 ( sinucosu + x )

==> 2 ( sinx^2cosx^2 +answer:

therefore,

2(sinx^2cosx^2 + 1 )

is your answer.

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