Question

differentiation of sin x / cos x is equal to sec Square X prove that​

Answer 1

Answer:

let y=sinx/cosx

dy/dx=[cosx.cosx - sinx.(-sinx)]/cosx^2.....(by divide rule)

dy/dx=[cos^2x + sin^2x]/cos^2x..(cos^2x+sin^2x =1)

dy/dx=1/cos^2x

dy/dx=sec^2x....(1/cosx=secx)

hence, proved