differentiation of sin[x+y/x-y]
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Differentiate the left side of the equation. Differentiate using the chain rule, which states that ddx[f(g(x))] d d x [ f ( g ( x ) ) ] is f'(g(x))g'(x) f ′ ( g ( x ) ) g ′ ( x ) where f(x)=sin(x) f ( x ) = sin ( x ) and g(x)=xy g ( x ) = x y .
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