Question

differentiation of (sinx)^1/2​

Answer 1

Answer:

Step-by-step explanation:

f(x) = (sin x)^(1 /2)

f '(x) = (1 /2) × (cos x) × (sin x)^(- 1 / 2)

= cos x / 2 × (sin x)^(1 / 2)

Answer 2

Step-by-step explanation:

d/dx (sinx)1/2

$\frac{ {cosx}^{ - \frac{1}{2} } }{2}$

$\frac{1}{2{cosx}^{2} }$