differentiation of (sinx)^logx
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(sinx)^logx=v
taking log on both side
log[(sinx)^logx]=logv
logx×log(sinx)=logv
differentiating both side
logx×1/sinx ×cosx+log(sinx)/X=1/v×dv/DX
[logx×cotx+ log(sinx)/X]×(sinx)^logx=DV/dx
taking log on both side
log[(sinx)^logx]=logv
logx×log(sinx)=logv
differentiating both side
logx×1/sinx ×cosx+log(sinx)/X=1/v×dv/DX
[logx×cotx+ log(sinx)/X]×(sinx)^logx=DV/dx
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