Differentiation of tan x ?
Please write the steps too .
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Answer:
diff. with x
d/dx tan x = 1/ cos²x
= sec²x
hope its help
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The derivative of tan x is sec2x. When the tangent argument is itself a function of x, then we use the chain rule to find the result.
The derivative of tanx is sec2x
#d/dx tanx = lim_(h->0) (tan(x+h)-tanx)/h# Using the trigonometric formulas for the sum of two angles: #tan(x+h) = sin(x+h)/cos(x+h)# ...
#tan(x+h) = (tanx+tan(h))/(1-tanx tan(h))# So: ...
#d/dx tanx = (1+tan^2x ) lim_(h-
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