Question

differentiation of tanx.cosx​

Answer 1

y=tan(x)cos(x) (take log from both sides)

lny=cos(x)ln(tanx) (take derivative form both sides)

y'/y=(cos(x)ln(tan(x)))'=-sin(x)ln(tan(x))+1/sin(x)

y'=y sin(x)(1/sin2(x)-ln(tan(x))

Answer 2

$Here is your answer$

$tanx.cosx$

$sinx$

d.w.r.t.x

cosx.....✏️✏️

✍️✍️ please mark it brainlist answer..