Question

differentiation of x(1+logx) ​

Answer 1

Answer:

(1+logx)+1

Step-by-step explanation:

It is in the product way

(uv) = u'v+v'u

Consider u=x, v=1+logx

d/dx (x)(1+logx)+(1+logx)x

1(1+logx)+1/x(x)

1+logx+1