differentiation of x^2 cos x.
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0
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PLEASE REFER TO THE ATTACHMENT!!
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its just a question of 5 lines .
don't know what they are solving and what they want to show here ..
using product rule = (uv)'= u' v+ v'u
so,
The first derivative of x² = 2x
The first derivative of cosx = -sinx
using both in rule :-
(x²cosx)' = 2xcosx - x²sinx (Ans)
(Mark as brainlist now )
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