Question

Differentiation of x^3/2 -sin^2x is *
3/2 x^5/2 - 2sinx cosx
3/2 x^1/2 - 2sinx cosx
3/2 x^5/2 - 2 sinx
5/2 x^5/2 - 2sinx cosx

Answer 1

Explanation:

given that ,y = x^3/2 -sin²2x

dy/dx = 3/2 x^ 1/2 - 2sinxcosx

so option B will be correct answer

pls like my solution