differentiation of x^3 (x+1) (x^2 + 1)
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Answer:
dy/dx=6x⁵+2x⁴ +4x³+6x²
Step-by-step explanation:
y=x^3 (x+1) (x^2 + 1)
=(x^4+x^3)(x^2+1)
dy/dx=(x^4+x^3)d/dx(x^2+1)+(x^2+1)d/dx(x^4+x^3)
=(x^4+x^3) (2x) + (x^2+1) (4x^3+3x^2)
=2x⁵+2x⁴ +4x⁵+3x²+4x³+3x²
dy/dx=6x⁵+2x⁴ +4x³+6x²
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