differentiation of x= v not t + 1\2 at^2
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How do you differentiate 2 to the power x?
1. let y=2x {take natural logs of both sides}
2. ln y = ln(2x) {use rules of logs to change right hand side}
3. lny = xln2 {differentiate implicitly}
4. 1/y . dy/dx = ln2 {make dy/dx the subject}
dy/ dx = y ln2 {write y in terms of x)
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v=d/t ;d=vt a=d/t^2 ;d=at^2 1/2d+1/2d=1/2vt+1/2at^2 d=1/2(vt+at^2)
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