differentiation of x^x.....???
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let y=x^x
taking log both sides
logy=xlogx
dwrtx
1/ydy/dx=1+logx
dy/dx=x^x(1+logx)
taking log both sides
logy=xlogx
dwrtx
1/ydy/dx=1+logx
dy/dx=x^x(1+logx)
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mathemagician:
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Step-by-step explanation:
Please refer the attached picture for the Step-by-step solution for the given problem.
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