Math, asked by mathemagician, 1 year ago

differentiation of x^x.....???

Answers

Answered by Anonymous

let y=x^x
taking log both sides
logy=xlogx
dwrtx
1/ydy/dx=1+logx
dy/dx=x^x(1+logx)

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Answered by GeniusYH

Answer:

$x^{x} (1 + ln(x))$

Step-by-step explanation:

Please refer the attached picture for the Step-by-step solution for the given problem.

Hoping that I have not made any mistakes, You're welcome.

Hope you have found my answer useful. If my answer deserves a brainliest, do mark it.

GeniusH

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